A tug of war for electrons

Section 1 of 4

A bond, as you have seen, is a pair of electrons shared by two atoms. Two hydrogen atoms in H–⁠H are exactly alike, so they share their pair exactly evenly. When the two atoms are different, one of them can pull the pair closer to itself.

Picture a tug of war with the shared pair as the rope. Each atom's nucleus is positive, and it pulls on the negative electrons. How strongly an atom pulls on a shared pair is called its electronegativity. The atom that pulls harder keeps the pair closer to it, and the electrons spend more of their time at its end of the bond.

Where the shared pair sits in three bonds Three ball-and-stick bonds, each with its shared pair of electrons drawn as two dots on the bond. In H–H the pair sits exactly in the middle. In C–H it sits almost in the middle, just a little closer to the carbon. In O–H the pair sits much closer to the oxygen, which pulls harder. H–⁠H an even share C–⁠H almost even O–⁠H closer to O
The shared pair sits in the middle of H–⁠H, almost in the middle of C–⁠H, and much closer to the oxygen in O–⁠H.

Who pulls hardest

Fluorine, oxygen, nitrogen and chlorine are strong pullers. Fluorine, oxygen and nitrogen keep their outer electrons in the same shell as carbon, and they have more protons in their nucleus (9, 8 and 7, against carbon's 6), so they grip a shared pair more tightly. Carbon and hydrogen pull with almost the same strength, so a C–⁠H bond shares its pair almost evenly.

How strongly each atom pulls on a shared pair (electronegativity on the Pauling scale)
AtomPull
fluorine, F3.98
oxygen, O3.44
chlorine, Cl3.16
nitrogen, N3.04
carbon, C2.55
hydrogen, H2.20

What matters in a bond is the gap between the two numbers. Oxygen and hydrogen are 1.24 apart, a big gap, so an O–⁠H bond shares very unevenly. Carbon and hydrogen are only 0.35 apart, so a C–⁠H bond shares almost evenly. A C–⁠C bond joins two identical atoms, so it shares exactly evenly, just like H–⁠H.

Quick check

Which of these bonds shares its electrons most evenly?